(1/2x-6)(8x^2-4x-10)

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Solution for (1/2x-6)(8x^2-4x-10) equation:


x in (-oo:+oo)

((1/2)*x-6)*(8*x^2-(4*x)-10) = 0

((1/2)*x-6)*(8*x^2-4*x-10) = 0

(1/2*x-6)*(8*x^2-4*x-10) = 0

8*x^2-4*x-10 = 0

2*(4*x^2-2*x-5) = 0

4*x^2-2*x-5 = 0

DELTA = (-2)^2-(-5*4*4)

DELTA = 84

DELTA > 0

x = (84^(1/2)+2)/(2*4) or x = (2-84^(1/2))/(2*4)

x = (2*21^(1/2)+2)/8 or x = (2-2*21^(1/2))/8

2*(x-((2-2*21^(1/2))/8))*(x-((2*21^(1/2)+2)/8)) = 0

2*(1/2*x-6)*(x-((2-2*21^(1/2))/8))*(x-((2*21^(1/2)+2)/8)) = 0

( 1/2*x-6 )

1/2*x-6 = 0 // + 6

1/2*x = 6 // : 1/2

x = 6/1/2

x = 12

( 2 )

2 = 0

x belongs to the empty set

( x-((2*21^(1/2)+2)/8) )

x-((2*21^(1/2)+2)/8) = 0 // + (2*21^(1/2)+2)/8

x = (2*21^(1/2)+2)/8

( x-((2-2*21^(1/2))/8) )

x-((2-2*21^(1/2))/8) = 0 // + (2-2*21^(1/2))/8

x = (2-2*21^(1/2))/8

x in { 12, (2*21^(1/2)+2)/8, (2-2*21^(1/2))/8 }

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